Bay 12 Games Forum

Ok this is very BASIC: however it involves really pushing the idea of futuristic tech.

Uranium!- Comes from pitcheblende-First- Forge a uranium bar, then enrich it, then you convert matter via atomic power to make a stone into coke.
However, plutonium may be a by-product of enrichment, and can be used in a seperate reaction to make coke, however it will cause explosion( or so I think as I have yet to test it) but makes 10 coke!

[MATGLOSS_STONE:PITCHBLENDE]
[NAME:pitchblende][COLOR:5:7:0][TILE:'*']
[ENVIRONMENT:IGNEOUS_EXTRUSIVE:VEIN:100]
[ENVIRONMENT_SPEC:GRANITE:CLUSTER_SMALL:100]
[ITEM_SYMBOL:'*']
[METAL_ORE:URANIUM:100]
[SOLID_DENSITY:30000]
[VALUE:100]



[MATGLOSS_METAL:URANIUM]
[NAME:uranium][ADJ:uranium][COLOR:0:7:1]
[VALUE:100]
[SPEC_HEAT:1500]
[MELTING_POINT:12768]
[BOILING_POINT:15150]
[WEAPON][DIGGER]
[DAMAGE_PERC:105]
[BLOCK_PERC:70]
[SOLID_DENSITY:30000]



[REACTION:PITCHE_TO_URANIUM]
[NAME:make uranium bars]
[SMELTER]
[REAGENT:2:METAL_ORE:URANIUM]
[PRODUCT:100:2:BAR:NO_SUBTYPE:METAL:URANIUM]
[FUEL]



[MATGLOSS_METAL:PLUTONIUM]
[NAME:plutonium][ADJ:plutonium][COLOR:0:7:1]
[VALUE:150]
[SPEC_HEAT:1500]
[MELTING_POINT:12768]
[BOILING_POINT:15150]
[BRITTLE]
[DAMAGE_PERC:110]
[BLOCK_PERC:20]
[SOLID_DENSITY:42000]



[REACTION:ENRICHMENT]
[NAME:enrich uranium]
[SMELTER]
[REAGENT:2:METAL_ORE:URANIUM]
[PRODUCT:100:7:BAR:NO_SUBTYPE:METAL:EURANIUM]
[PRODUCT:20:3:BAR:NO_SUBTYPE:METAL:PLUTONIUM]
[FUEL]



[MATGLOSS_METAL:EURANIUM]
[NAME:enriched uranium][ADJ:enriched uranium][COLOR:0:7:1]
[VALUE:100]
[SPEC_HEAT:1600]
[MELTING_POINT:12768]
[BOILING_POINT:15150]
[WEAPON][DIGGER][AMMO]
[DAMAGE_PERC:110]
[BLOCK_PERC:80]
[SOLID_DENSITY:31000]



[REACTION:CONVERT_MATTER]
[NAME:re-molecularize stone]
[SMELTER]
[REAGENT:1:STONE:NO_SUBTYPE:STONE:NO_MATGLOSS]
[REAGENT:1:BAR:NO_SUBTYPE:METAL:EURANIUM]
[PRODUCT:100:2:BAR:NO_SUBTYPE:COAL:COKE]
[FUEL]



[REACTION:CONVERT_MATTER_P]
[NAME:dangerously re-molecularize stone into coke]
[SMELTER]
[REAGENT:1:STONE:NO_SUBTYPE:STONE:NO_MATGLOSS]
[REAGENT:1:BAR:NO_SUBTYPE:METAL:PLUTONIUM]
[PRODUCT:100:10:BAR:NO_SUBTYPE:COAL:COKE]
[PRODUCT:100:20:BAR:NO_SUBTYPE:METAL:UNSTABLESUBSTANCE]
[FUEL]



[MATGLOSS_METAL:UNSTABLESUBSTANCE]
[NAME:unstable matter][ADJ:unstable matter][COLOR:2:7:1]
[VALUE:200000]
[SPEC_HEAT:1]
[MELTING_POINT:1]
[BOILING_POINT:2]
[SOLID_DENSITY:40000000000]

I noticed a couple problems with your usage of d's.  Namely the ((dC+L+S)-J)/dt bit.

Let's see if I can fix the formula...

let D = density
let M = max trees
let A = area
let T = trees cut
let G = trees grown
let G0 = initial trees on map
let C = base cutting rate
let L = skill level modifier
let S = stat modifier (Agility)
let Rl = base rate of skill gain per trees cut = dL/dT
let Rs = base rate of stat gain per trees cut = dS/dT
let Rsj = base rate of stat gain when doing things other than cutting trees
let Rt = base rate of tree growth
let J = percentage of time actually spent with tree cutting job (including traveling, so if there was no other job than cutting, this would be 1.00 or 100% )

then,

dT/dt = J*(S*D+C*L)
D = A/(G0+G-T)
dG/dt = Rt*(M-(G+G0-T))
dL/dt = J*Rl*dT/dt
dS/dt = J*Rs*dT/dt + (1-J)*Rsj

We can at least do a bit of work on this.

let L0 = initial level
let S0 = initial skill

L = J*Rl*T+L0
S = J*Rs*T + t*Rsj*(1-J)+S0

So can reduce it to two simultainuous differential equations.

dT/dt = J*(A*(J*Rs*T + t*Rsj*(1-J)+S0)/(G0+G-T)+C*(J*Rl*T+L0))
dG/dt = Rt*(M-(G+G0-T))

let Q = current trees standing = G+G0-T

then we can write the equations simply as:

dT/dt = J*(A*(J*Rs*T + t*Rsj*(1-J) + S0)/Q + C*(J*Rl*T+L0))
dG/dt = Rt*(M-Q)

next, differentiate Q

dQ/dt = dG/dt-dT/dt

factor, as much as possible, each equation into terms of T, Q, and G
dT/dt = (J*J*A*Rs*T+J*A*Rsj*t-J*J*Rsj*t+J*S0)/Q + (C*J*Rl)*T +C*L0
Q*dT/dt = T*(J*J*A*Rs+(C*J*Rl)*Q)+t*(J*A*Rsj-J*J*Rsj+(C*L0))+Q*(C*L0)+J*J*A*S0

we end up with something of the form:

Q*dT/dt = (k1+k2*Q)*T+k3*t+k4*Q+k5

differentiate both sides:

QT''+Q'T' = k1T'+k2QT'+k2Q'T+k4*Q'+k3
QT''+Q'T' = (k2T')Q+(k2T+k4)Q'+k1T'+k3

further solving is left as an exercise for the student.

Alas I said: This formula is very basic and many things are left out or assumed.  I would differentiate both sides - however I lack the time or patient for a large problem. But taking quick glimpses of your formula. Ok Now assuming the k's are constants - because it just makes sense.

So far, Q= [Q'(K2T+K4-T')+K1t'+k3]/(T''-K2T')

I run into trouble further when trying to figure out what the K's represent as constants.

However I remember the question is of the rate of trees cut so T' needs to be solved for too.

T=[T'(Q'-K1-K2Q)-K4Q'-K3+QT'']/(K2Q')

T'=[Q'(K2T+K4)+K3-QT'']/(Q'-K1-K2Q)

Maybe the desolateness of the fallout mod has made them evolve? - I have already lost 10 people to hunting...

In my vault society - I focus on hunting - however the non-seasoned hunters die left and right to fire geckos. Ripped throats!

I made fortress in 39f, (with fallout mod) and my hunters hunt in groups!

Mr.Handies thiefs are quick, however my sniper and .229 ammo!

Thus if you find the rate of woodcut per time you can then use a intergration to calculate the amount of woodcut by a certain time.

Well, I know you can remove the M - however I left it in due to laziness and to make it make more sense to less math inclined people. However currently it doesn't fit the expression.

It would actually be M/dt- as it has to be to make sense with the other rates.

so it is more like: (dT-((dC+L+S)-J))/dt=dA(rate of trees cut overall)