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[Zironic]

Me and my friend started joking around on how much wood can a woodcutter cut if a woodcutter could cut wood on a 1x1 map.

this is the formula so far.

(M-(dT/dt-((dC+L+S)-J)/dt))-M

M would be the maximum amount of trees for the map,

dT/dt is the rate of tree growth,

(dC is the rate of basic wood cutting,

L is the level of skill in cutting (in speed),

S is the stat ( agility mainly)

J is the time taken doing other things on average)

and dt at the end is again making it a rate.

The Idea is - the amount of trees the map has maximum minus the rate at the current second of wood removal, then minus by the maximum equals the amount of wood cut.

Please add!

[Skanky]

Me and my friend started joking around on how much wood can a woodcutter cut if a woodcutter could cut wood on a 1x1 map.

The math escapes me, so I'll just put my answer down as "all of it".

[Zironic]

I mean please add on to it >.<

[Christes]

Abuse of notation hurts my eyes

[Angry Lawyer]

This is like the crap that advertising firms put into newspapers under the guise of "science", and giving science a bad name. D:

-Angry Lawyer

[Moon Label]

this is the formula so far.

I believe that would be an expression, since equations and formulas require equation marks.

In other words;
=

[LordZabujca]

(M-(dT/dt-((dC+L+S)-J)/dt))-M

Now this expression is rather silly. Why do you need M (eliminate the brackets to see what I mean)? dT/dt may be the rate of growth, but what is dt itself? Also, the units don't match. You are adding time to unitless numbers to "stats" there. So yeah, this doesn't work at all.

[Ubersoldat]

Clearly, the answer is "Enough to piss off the elves."

[WillNZ]

This is a joke. Here is the serious evidence.   

This line:

how much wood can a woodcutter cut if a woodcutter could cut wood

is a play off of this tongue twister:

how much wood could woodchuck chuck if a woodchuck could chuck wood?

I rest my serious case. 

[Zironic]

Well, I know you can remove the M - however I left it in due to laziness and to make it make more sense to less math inclined people. However currently it doesn't fit the expression.

It would actually be M/dt- as it has to be to make sense with the other rates.

so it is more like: (dT-((dC+L+S)-J))/dt=dA(rate of trees cut overall)

[Eita]

Wait, what? What are you trying to find? The thread title makes it sound like you want to know how much wood can be cut in a given amount of time.

[Zironic]

Thus if you find the rate of woodcut per time you can then use a intergration to calculate the amount of woodcut by a certain time.

[Eita]

Indeed. I have no idea why he complicated the thing by adding forest growth.

[Draco18s]

Indeed. I have no idea why he complicated the thing by adding forest growth.

If trees grow back he can cut more wood....

Wait.

You're right.  It doesn't ***ing matter.

[Dogman]

Indeed. I have no idea why he complicated the thing by adding forest growth.

If trees grow back he can cut more wood....

Wait.

You're right.  It doesn't ***ing matter.

If he wants to know how long it takes to clear out an entire map of wood, then yes, knowing the growth rate of new trees is important.